Type Challenges Judge

Problems

Progress

Concat

提出詳細

type Tuple = readonly any[];

type Concat<T extends Tuple, U extends Tuple> = [...T, ...U];
提出日時2024-08-26 22:49:05
問題Concat
ユーザーKatsukiniwa
ステータスAccepted
テストケース
import type { Equal, Expect } from '@type-challenges/utils'

type cases = [
  Expect<Equal<Concat<[], []>, []>>,
  Expect<Equal<Concat<[], [1]>, [1]>>,
  Expect<Equal<Concat<[1, 2], [3, 4]>, [1, 2, 3, 4]>>,
  Expect<Equal<Concat<['1', 2, '3'], [false, boolean, '4']>, ['1', 2, '3', false, boolean, '4']>>,
]