Type Challenges Judge

Chainable Options

提出詳細

type Chainable<C extends object = {}> = { option<K extends string, V>(key: K extends keyof C ? never:K, value: V): Chainable<C & Record<K, V>>; get(): C }
提出日時2022-06-27 11:34:04
問題Chainable Options
ユーザーwaki285
ステータスAccepted
テストケース
import type { Alike, Expect } from '@type-challenges/utils' declare const a: Chainable const result1 = a .option('foo', 123) .option('bar', { value: 'Hello World' }) .option('name', 'type-challenges') .get() const result2 = a .option('name', 'another name') // @ts-expect-error .option('name', 'last name') .get() type cases = [ Expect<Alike<typeof result1, Expected1>>, Expect<Alike<typeof result2, Expected2>>, ] type Expected1 = { foo: number bar: { value: string } name: string } type Expected2 = { name: string }